Can I load an image in Pillow using Python’s open() like this?

[Rajeev Bagra]

 

❓ Question

Can I load an image in Pillow using Python’s open() like this?

with open("photo.jpg") as f:
    img = Image(f)

Instead of:

img = Image.open("photo.jpg")

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✅ Answer

No, this will not work.
Pillow images must be loaded using Image.open(), not by directly passing a file object to Image().

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🧠 Why doesn’t Image(f) work?

• open("photo.jpg") returns a file object (raw bytes).
• Image is not a constructor for creating images from file objects.
• Pillow needs to decode image formats (JPEG, PNG, etc.), and that logic exists only inside Image.open().

So this code is invalid:

img = Image(f)   # ❌ Incorrect

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✅ Correct and Recommended Way

from PIL import Image

img = Image.open("photo.jpg")
img.show()

This:

• Reads the image file
• Decodes the image format
• Returns a PIL.Image.Image object

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✅ Advanced (Using with open) — When Needed

If you must use open(), do it in binary mode and still call Image.open():

from PIL import Image

with open("photo.jpg", "rb") as f:
    img = Image.open(f)
    img.show()

When is this useful?

• Loading images from streams
• Reading images from memory (BytesIO)
• Handling uploaded or downloaded images

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🔑 Key Difference to Remember

Function	Purpose
open()	Reads raw file bytes
Image.open()	Decodes image and creates Image object
Image()	❌ Not used to load images

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📌 Conclusion

✔ Always use Image.open() to load images in Pillow
❌ Do not try to create images using Image(f)
✔ Use open(..., "rb") only when working with streams

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