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January 5, 2026 at 5:00 am #5925

🔰 Initial Context (Read Before the Q&A)
This topic comes from image steganography, a technique used to hide one image inside another.
The hidden image is embedded inside the Least Significant Bits (LSBs) of pixel values.
Because LSB changes alter pixel intensity by only ±1, the visible image looks unchanged to the human eye.Your task is to:
- Extract hidden data from the LSBs
- Rebuild the hidden image
- Rescale pixel values so the image becomes visible
This guide explains both grayscale (BW) and RGB image recovery in one place.
📌 Background You Must Know
What is an 8-bit image?
An 8-bit image uses 8 binary digits per channel:
[
2^8 = 256 \Rightarrow \text{pixel values range from } 0 \text{ to } 255
]0→ black255→ white
Pixel representation
Image Type Pixel Representation Grayscale (BW) pRGB (r, g, b)
🧩 Helper Function (Given)
def extract_end_bits(num_end_bits, pixel): return pixel % (2 ** num_end_bits)For this problem:
- We always use
num_end_bits = 1 - Output is either
0or1
🧪 Core Idea (Same for BW & RGB)
- Extract LSB(s)
- Get values
0or1 - Rescale:
0 → 01 → 255
- Build a new image
🧠 Combined Q&A (Grayscale + RGB)
Q1. What does “recovering a hidden image” mean?
Answer:
It means extracting a secret image that has been invisibly embedded inside another image by using the least significant bits of pixel values.
Q2. Why are LSBs used to hide images?
Answer:
Because changing an LSB:- Alters pixel value by only
±1 - Does not create visible distortion
- Is ideal for hiding information securely
Q3. How is data stored in a grayscale (BW) image?
Answer:
Each grayscale pixel stores one 8-bit value.
The hidden image is stored in the LSB of that value.
Q4. How is data stored in an RGB image?
Answer:
Each RGB pixel stores three 8-bit values:- Red channel
- Green channel
- Blue channel
Each channel hides one LSB, so one RGB pixel can hide three bits.
Q5. Why does extracting LSBs produce a very dark image?
Answer:
Because the extracted values are only0or1, which lie at the very bottom of the brightness range.
Q6. Why do we rescale
1 → 255?Answer:
To stretch the recovered image across the full intensity range, making details visible to the human eye.
Q7. What is the difference in recovery logic between BW and RGB?
Answer:
Step Grayscale RGB Values per pixel 1 3 LSBs extracted 1 3 Output pixel 0 or 255(0/255, 0/255, 0/255)The logic is identical; RGB simply repeats it three times per pixel.
Q8. How do we recover a grayscale image? (Conceptual Code)
def reveal_bw_image(filename): img = Image.open(filename).convert("L") w, h = img.size out = Image.new("L", (w, h)) for x in range(w): for y in range(h): bit = extract_end_bits(1, img.getpixel((x, y))) out.putpixel((x, y), 255 if bit else 0) return out
Q9. How do we recover an RGB image? (Conceptual Code)
def reveal_rgb_image(filename): img = Image.open(filename).convert("RGB") w, h = img.size out = Image.new("RGB", (w, h)) for x in range(w): for y in range(h): r, g, b = img.getpixel((x, y)) out.putpixel((x, y), ( 255 if extract_end_bits(1, r) else 0, 255 if extract_end_bits(1, g) else 0, 255 if extract_end_bits(1, b) else 0 )) return out
Q10. How should
reveal_imagehandle both cases?Answer:
reveal_imageshould:- Inspect image mode
- Call:
reveal_bw_imagefor"L"reveal_rgb_imagefor"RGB"
- Return the recovered
PIL.Image
Q11. Should the recovered image’s type match the original?
Answer:
Yes.- Grayscale → Grayscale output
- RGB → RGB output
Q12. Where is this technique used in real life?
Answer:
- Digital watermarking
- Copyright protection
- Secure image communication
- Forensics
- Academic image processing
✅ Final Summary
- 8-bit images use values
0–255 - Hidden data lives in LSBs
- Grayscale → 1 bit per pixel
- RGB → 3 bits per pixel
- Rescaling is essential
- Same logic, different channels
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