Assigning keys to plaintext with ASCII

[dm_code_snippet background=”yes” background-mobile=”no” slim=”yes” line-numbers=”yes” bg-color=”#abb8c3″ theme=”dark” language=”clike” wrapped=”yes” height=”” copy-text=”Copy Code” copy-confirmed=”Copied”]

 for (int i = 0; i < countstring; i++) //starts with first character of plaintext till the end
{
    for (int c = 0; c < 25; c++)
    {
        if (s[i] == argv[1][c])
        {
        s[i] == int argv[1][65 + c];
        }
     }
}
printf("ciphertext: %s", s);

[/dm_code_snippet]

Seeking help what is wrong with s[i] == int argv[1][65 + c];

Reply

assignment operation = is different than equality condition ==

Query

s[i] == int argv[1][65 + c];

Do you mean, it should be:

s[i] = int argv[1][65 + c];

instead of:

s[i] == int argv[1][65 + c];

Reply

aren’t you trying to “assign” the value of argv[][] to s[]?

Query

Yes.

Reply

then use assignment operator[learn_press_profile]